# Is 141 a prime number?

It is possible to find out using mathematical methods whether a given integer is a prime number or not.

For 141, the answer is: No, 141 is not a prime number.

The list of all positive divisors (i.e., the list of all integers that divide 141) is as follows: 1, 3, 47, 141.

For 141 to be a prime number, it would have been required that 141 has only two divisors, i.e., itself and 1.

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As a consequence:

For 141 to be a prime number, it would have been required that 141 has only two divisors, i.e., itself and 1.

However, 141 is a **semiprime** (also called biprime or 2-almost-prime), because it is the product of a two non-necessarily distinct prime numbers. Indeed, 141 = 3 x 47, where 3 and 47 are both prime numbers.

### Is 141 a deficient number?

Yes, 141 is a deficient number, that is to say 141 is a natural number that is strictly larger than the sum of its proper divisors, i.e., the divisors of 141 without 141 itself (that is 1 + 3 + 47 = 51).